Geometric Sequences: Exponential Growth
Each term is the previous times common ratio r: aₙ = a₁r^(n−1). Sum Sₙ = a₁(1−rⁿ)/(1−r) when r≠1. Infinite sum S∞ = a₁/(1−r) when |r|<1.
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Compound interest: balance = P(1+r)^n — geometric with a₁=P, ratio=1+r. 1+1/2+1/4+... = 2 — infinite geometric with r=1/2. |r|≥1: infinite sum diverges.
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Why: Geometric sequences model exponential growth: compound interest, population, radioactive decay. Ratio r: each term = previous × r. |r|<1 gives convergent infinite sum.
How: nth term: aₙ = a₁×r^(n−1). Sum: Sₙ = a₁(1−rⁿ)/(1−r). Infinite: S∞ = a₁/(1−r) when |r|<1. Common ratio r = a₂/a₁.
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Term Values
Term Distribution
📐 Step-by-Step Breakdown
For educational and informational purposes only. Verify with a qualified professional.
🧮 Fascinating Math Facts
aₙ = a₁r^(n−1). Sum Sₙ = a₁(1−rⁿ)/(1−r).
Compound interest is geometric: P(1+r)^n.
📋 Key Takeaways
- • nth term: aₙ = a₁ × r^(n-1), where a₁ is first term, r is common ratio
- • Sum of n terms: Sₙ = a₁(1-rⁿ)/(1-r) when r ≠ 1; Sₙ = n×a₁ when r = 1
- • Infinite sum: S∞ = a₁/(1-r) only when |r| < 1
- • Common ratio: r = a_n+1/a_n for any consecutive terms
- • Each term is a constant multiple of the previous term
💡 Did You Know?
📖 How It Works
A geometric sequence: a₁, a₁r, a₁r², a₁r³, ... Each term is a₁ × r^(n-1). The sum of the first n terms uses Sₙ = a₁(1-rⁿ)/(1-r) when r ≠ 1. When |r| < 1, the infinite series converges to a₁/(1-r).
📝 Worked Example: 2, 6, 18, 54... — 5th term and sum
Given: a₁ = 2, r = 3
5th term: a₅ = 2 × 3^4 = 2 × 81 = 162
Sum of 5 terms: S₅ = 2(1-3⁵)/(1-3) = 2(1-243)/(-2) = 2×242/2 = 242
Verification: 2+6+18+54+162 = 242 ✓
🚀 Real-World Applications
💰 Compound Interest
Investment growth: principal × (1+r)^n each period.
📉 Radioactive Decay
Half-life: amount halves each period.
🦠 Population Growth
Exponential growth with constant doubling time.
📺 Viral Spread
Each person infects r others — geometric spread.
🎵 Musical Scales
Frequency ratios in equal temperament.
📊 Annuities
Present value of future payments.
⚠️ Common Mistakes to Avoid
- Wrong exponent: aₙ = a₁ × r^(n-1), not r^n. For a₅, exponent is 4.
- r = 1: Sum formula Sₙ = a₁(1-rⁿ)/(1-r) is undefined when r=1. Use Sₙ = n×a₁.
- Infinite sum when |r| ≥ 1: Series diverges — no finite sum.
- Negative r: Terms alternate sign; sum formula still works.
- Finding r: r = a₂/a₁, not a₁/a₂.
🎯 Expert Tips
💡 Find r
Divide any term by the previous: r = aₙ₊₁ / aₙ
💡 Find a₁
a₁ = aₙ / r^(n-1) if you know the nth term
💡 Convergence
Infinite sum exists only when |r| < 1
💡 r = 1
All terms equal; Sₙ = n × a₁
📊 Reference Table
| Formula | Use When |
|---|---|
| aₙ = a₁ × r^(n-1) | Finding nth term |
| Sₙ = a₁(1-rⁿ)/(1-r) | r ≠ 1 |
| Sₙ = n × a₁ | r = 1 |
| S∞ = a₁/(1-r) | |r| < 1 |
📐 Quick Reference
🎓 Practice Problems
❓ FAQ
What is a geometric sequence?
A sequence where each term is the previous term multiplied by a constant (common ratio r).
How do I find the common ratio?
Divide any term by the previous: r = aₙ₊₁ / aₙ.
When does the infinite sum exist?
Only when |r| < 1. Then S∞ = a₁/(1-r).
What if r = 1?
All terms are equal. Sₙ = n × a₁.
Applications?
Compound interest, population growth, radioactive decay, annuities.
Difference from arithmetic sequence?
Geometric multiplies by r; arithmetic adds d.
Can r be negative?
Yes. Terms alternate sign. Sum formula still works.
📌 Summary
Geometric sequences multiply by a constant r. Use aₙ = a₁ × r^(n-1) for the nth term and Sₙ = a₁(1-rⁿ)/(1-r) for the sum when r ≠ 1. When |r| < 1, the infinite sum converges to a₁/(1-r).
✅ Verification Tip
Check that aₙ₊₁ / aₙ = r for consecutive terms. For sum, add the first few terms manually and compare.
🔗 Next Steps
Explore the Arithmetic Sequence Calculator for additive growth, or the Summation Calculator for sigma notation. The Logarithm Calculator relates to geometric sequences.
⚠️ Disclaimer: This calculator is for educational purposes. Verify critical calculations independently.
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