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Divisibility Test

Check if a number is divisible by integers from 1 to 12 with explanations of divisibility rules.

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divisibility.sh
CALCULATED
$ check --n=144
Input
144
Divisible by
8 of 12
Divisors
1, 2, 3, 4, 6, 8, 9, 12
Prime factors
2×2×2×2×3×3
Divisibility Test Calculator
144 divisible by 1, 2, 3, 4, 6, 8, 9, 12
numbervibe.com
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Divisibility by 1–12

Divisible vs Not

📐 Step-by-Step Breakdown

SETUP
Inputn = 144
METHOD
Prime factors2 × 2 × 2 × 2 × 3 × 3
÷1Yes
÷2Yes
÷3Yes
÷4Yes
÷6Yes
÷8Yes
÷9Yes
÷12Yes

For educational and informational purposes only. Verify with a qualified professional.

📋 Key Takeaways

  • • 2: last digit even
  • • 3: sum of digits divisible by 3
  • • 4: last two digits divisible by 4
  • • 5: last digit 0 or 5
  • • 6: divisible by both 2 and 3
  • • 9: sum of digits divisible by 9
  • • 10: last digit 0

💡 Did You Know?

🔢2520 is the smallest number divisible by 1 through 10.Source: LCM
📐Rule for 7: double last digit, subtract from rest. Repeat.Source: Divisibility
🎯11: alternating sum of digits divisible by 11.Source: Modular
📊12: divisible by both 3 and 4.Source: Composite
🔬Prime factorization helps find all divisors.Source: Number Theory
📐Divisibility rules avoid long division.Source: Shortcuts

📖 How It Works

Divisibility rules are shortcuts to check if a number divides another without performing full division. Each divisor from 2 to 12 has a rule based on digit patterns.

📝 Worked Example: 144

÷2: Last digit 4 (even) ✓

÷3: 1+4+4 = 9, 9÷3 ✓

÷4: Last two 44, 44÷4 ✓

÷6: ÷2 and ÷3 ✓

🎯 Expert Tips

  • Combine rules: 6 = 2 and 3, 12 = 3 and 4
  • Use prime factorization to find all divisors
  • Sum of digits for 3 and 9
  • Last-digit rules for 2, 5, 10

📊 Reference Table

DivisorRule
2Last digit even
3Sum of digits ÷ 3
4Last 2 digits ÷ 4
5Last digit 0 or 5
6÷2 and ÷3
9Sum of digits ÷ 9
10Last digit 0
11Alternating sum ÷ 11
12÷3 and ÷4

❓ FAQ

How to check divisibility by 7?

Double the last digit, subtract from the rest. Repeat until small enough.

What about 11?

Alternating sum of digits (1st−2nd+3rd−...) divisible by 11.

Why does sum of digits work for 3?

10 ≡ 1 (mod 3), so 10^n ≡ 1, hence the number ≡ sum of digits (mod 3).

What is 2520?

Smallest number divisible by 1 through 10 (LCM of 1..10).

How to find all divisors?

Use prime factorization. All divisors are products of prime factors.

Is 0 divisible by any number?

Yes. 0 ÷ n = 0 for any n ≠ 0.

⚠️ Disclaimer: Results are for educational purposes.

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