ALGEBRAAlgebraMathematics Calculator
📐

Eigenvalue Decomposition

Diagonalize A as A=PDP⁻¹: P has eigenvectors as columns, D has eigenvalues on the diagonal. Enables easy computation of Aⁿ=PDⁿP⁻¹. Used in Markov chains, differential equations, and PCA.

Concept Fundamentals
Decomposition
A=PDP⁻¹
PDⁿP⁻¹
Aⁿ
max|λᵢ|
ρ(A)
n lin indep eigenvectors
Diagonalizable

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Not all matrices are diagonalizable (need n independent eigenvectors). Spectral radius ρ(A)=max|λᵢ| determines long-term growth/decay. Markov chains: steady state is eigenvector for λ=1.

Key quantities
Decomposition
A=PDP⁻¹
Key relation
PDⁿP⁻¹
Aⁿ
Key relation
max|λᵢ|
ρ(A)
Key relation
n lin indep eigenvectors
Diagonalizable
Key relation

Ready to run the numbers?

Why: Diagonalization simplifies matrix powers (Markov chains, Fibonacci), solves differential equations, and underlies PCA. Aⁿ=PDⁿP⁻¹ makes high powers tractable since Dⁿ is trivial.

How: Find eigenvalues and eigenvectors. Build P from eigenvectors (columns), D from eigenvalues (diagonal). Verify A=PDP⁻¹. For Aⁿ: compute Dⁿ (element-wise) and multiply PDⁿP⁻¹.

Not all matrices are diagonalizable (need n independent eigenvectors).Spectral radius ρ(A)=max|λᵢ| determines long-term growth/decay.

Run the calculator when you are ready.

Diagonalize MatricesA=PDP⁻¹, compute Aⁿ

Matrix A (2×2) & Power n

decomp_calc.sh
CALCULATED
$ decompose --matrix=[[3,1],[0,2]] --power=3
Eigenvalues
3.0000, 2.0000
Spectral Radius
3.0000
Verification
✅ A=PDP⁻¹
A^3
[[27.00,19.00],[0.00,8.00]]
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Eigenvalue Comparison

Matrix Component Contribution

📐 Calculation Breakdown

MATRIX A
Trace
5.0000
tr(A) = 3 + 2
Determinant
6.0000
det(A) = 3×2 - 1×0
EIGENVALUES
Characteristic polynomial
λ² - 5λ + 6
\text{lambda} ^{2} - ext{tr}(A)\text{lambda} + ext{det}(A) = 0
λ₁
3.0000
( ext{tr} + √\text{Delta} )/2
λ₂
2.0000
( ext{tr} - √\text{Delta} )/2
DECOMPOSITION
P (eigenvectors as columns)
[[1,1],[0,-1]]
D (eigenvalues on diagonal)
[[3.00,0],[0,2.00]]
Verification A = PDP⁻¹
✅ OK
PROPERTIES
Spectral radius ρ(A)
3.0000
\text{max}|\text{lambda} ᵢ|
A^3
[[27.00,19.00],[0.00,8.00]]

P (Eigenvector Matrix)

[[1.0000, 1.0000],
 [0.0000, -1.0000]]

D (Diagonal)

[[3.0000, 0.0000],
 [0.0000, 2.0000]]

For educational and informational purposes only. Verify with a qualified professional.

🧮 Fascinating Math Facts

📊

PCA: diagonalize covariance matrix to find principal components.

— ML

🎲

Markov: steady state = eigenvector for eigenvalue 1.

— Probability

📋 Key Takeaways

  • A = PDP⁻¹ diagonalizes A: P has eigenvectors as columns, D has eigenvalues on the diagonal
  • Aⁿ = PDⁿP⁻¹ — computing powers is easy once diagonalized (Dⁿ is element-wise)
  • • Diagonalization fails for defective matrices (fewer than n eigenvectors)
  • • Spectral radius ρ(A) = max|λᵢ| determines stability of iterative methods

💡 Did You Know?

🐰The Fibonacci sequence can be computed via matrix powers: F_n comes from [[1,1],[1,0]]^n.Source: Discrete Math
📊PCA diagonalizes the covariance matrix — eigenvectors are principal components, eigenvalues = variance.Source: Data Science
⚛️In quantum mechanics, diagonalizing the Hamiltonian gives energy eigenvalues and stationary states.Source: Quantum Physics
📈Markov chain steady states are the eigenvector for λ=1 of the transition matrix.Source: Probability
🔄Differential equations dx/dt = Ax: solution uses e^(At) = P e^(Dt) P⁻¹.Source: ODE Theory
⚠️Not all matrices are diagonalizable — e.g. [[1,1],[0,1]] has only one eigenvector (defective).Source: Linear Algebra

📖 How Diagonalization Works

A matrix A is diagonalizable if A = PDP⁻¹ for some invertible P and diagonal D. The columns of P are eigenvectors, and the diagonal of D contains the corresponding eigenvalues. This "change of basis" simplifies many computations.

When it fails: Defective matrices (e.g. [[1,1],[0,1]]) have repeated eigenvalues but fewer than n linearly independent eigenvectors. They require Jordan form instead of diagonalization.

🎯 Expert Tips

A^n via Decomposition

Aⁿ = PDⁿP⁻¹. Dⁿ = diag(λ₁ⁿ, λ₂ⁿ) — no matrix multiplication needed for D!

Spectral Radius

ρ(A) < 1 ⇒ Aⁿ → 0. ρ(A) = 1 ⇒ bounded. ρ(A) > 1 ⇒ diverges.

Symmetric Matrices

Real symmetric A: P can be chosen orthogonal (P⁻¹ = Pᵀ). Essential for PCA.

Verification

Always check PDP⁻¹ ≈ A. Small numerical error is normal; large error indicates a bug.

📖 How It Works — Step by Step

1. Find eigenvalues by solving det(A - λI) = 0. For 2×2: λ² - tr(A)λ + det(A) = 0.
2. Find eigenvectors for each λ by solving (A - λI)v = 0. These form the columns of P.
3. Build D as the diagonal matrix with eigenvalues: D = diag(λ₁, λ₂).
4. Compute P⁻¹ and verify A = PDP⁻¹. Then Aⁿ = PDⁿP⁻¹ where Dⁿ = diag(λ₁ⁿ, λ₂ⁿ).

📊 When Diagonalization Fails

ConditionResult
n distinct eigenvaluesAlways diagonalizable
Repeated eigenvalue, full eigenspaceDiagonalizable
Repeated eigenvalue, deficient eigenspaceDefective — use Jordan form
Complex eigenvalues (real matrix)Not diagonalizable over ℝ, use ℂ

❓ FAQ

What is A = PDP⁻¹?

The eigenvalue decomposition. P has eigenvectors as columns, D has eigenvalues on the diagonal. Changing to the eigenbasis makes A act as a diagonal (scaling) matrix.

Why compute A^n via decomposition?

Aⁿ = PDⁿP⁻¹. Dⁿ is trivial (just raise each diagonal entry to n). Direct matrix multiplication is O(n³) per power; decomposition is O(n³) once, then O(n²) per power.

What is the spectral radius?

ρ(A) = max|λᵢ|. For iterative methods (e.g. power iteration), convergence depends on ρ(A). ρ < 1 means the process converges to zero.

When is a matrix not diagonalizable?

Defective matrices have repeated eigenvalues but fewer linearly independent eigenvectors than the multiplicity. Example: [[1,1],[0,1]].

How does this relate to PCA?

PCA diagonalizes the covariance matrix Σ = PDPᵀ. The columns of P are principal components; eigenvalues give variance explained.

Can I use this for 3×3 matrices?

The same idea applies, but 3×3 requires solving a cubic for eigenvalues. This calculator focuses on 2×2 for clarity.

📋 Quick Reference

FormulaMeaning
A = PDP⁻¹Eigenvalue decomposition
Aⁿ = PDⁿP⁻¹Matrix power via diagonalization
Dⁿ = diag(λ₁ⁿ, λ₂ⁿ)Diagonal powers are element-wise
ρ(A) = max|λᵢ|Spectral radius
P columns = eigenvectorsEigenvector matrix

⚠️ Disclaimer: This calculator supports 2×2 matrices with real eigenvalues. Matrices with complex eigenvalues are not diagonalizable over the reals. For research, verify with MATLAB, NumPy, or similar.

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